A 739 mL gas sample at STP is compressed to

a volume of 244 mL, and the temperature is

increased to 24◦C. What is the new pressure

of the gas in Pa?

The new pressure is 3.295 × 10⁵ Pa

Explanation:

Given: Initial Volume: V₁ = 739 mL, Final Volume: V₂ = 244 mL,

At STP; Initial Temperature: T₁ = 273 K, Initial Pressure: P₁ = 10⁵ Pa,

Final Temperature: T₂ = 24°C = 24 + 273 = 297 K,    (∵ 0°C = 273.15 K)

Final Pressure: P₂ = ?          

According to the Combined Gas Law:

Therefore, the new or final pressure of the given gas: P₂ = 3.295 × 10⁵ Pa

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