A flexible vessel contains 32.00 L of gas at a pressure of 1.59 atm. Under conditions of constant temperature and moles of gas, what is the volume of the gas when the pressure of the vessel is decreased by a factor of three

When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L

Explanation:

Step 1: Data given

Volume of the gas = 32.00 L

Pressure of the gas = 1.59 atm

Temperature and moles of gas stay constant

the pressure of the vessel is decreased by a factor of three

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.59 atm

⇒with V1 = the initial volume = 32.00 L

⇒with P2 = the decreased pressure = 1.59 / 3 = 0.53 atm

⇒with V2 = the new volume = TO BE DETERMINED

1.59 atm * 32.00 L = 0.53 atm * V2

V2 = (1.59 * 32.00 L) / 0.53 atm

V2 = 96.00 L

When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L

the answer is 75.0%.

it is a solid

explanation: