Exactly 16 mL of a solution A is diluted to 300 mL, resulting in a new solution B that has 0.50 M concentration. If the solution was made with NaCl (58.443 g/mole), determine the number of grams of NaCl needed to make 1.00 L of the original solution A.

8.77g

Explanation:

Step 1:

Data obtained from the question.

This includes the following:

Concentration of A (C1) =.?

Volume of A (V1) = 16 mL

Volume of B (V2) = 300 mL

Concentration of B (C2) = 0.50 M

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =.?

Step 2:

Determination of the concentration of A.

Applying the dilution formula:

C1V1 = C2V2

The concentration of A i.e C1 can be obtained as follow:

C1V1 = C2V2

C1 x 16 = 0.5 x 300

Divide both side by 16

C1 = (0.5 x 300) / 16

C1 = 9.375 M

Therefore, the concentration of A is 9.375 M

Step 3:

Determination of the number of mole of NaCl in 9.375 M NaCl solution. This is illustrated below:

Molarity = 9.375 M

Volume = 16 mL = 16/1000 = 0.016 L

Mole of NaCl =?

Molarity = mole /Volume

Mole =Molarity x Volume

Mole of NaCl = 9.375 x 0.016

Mole of NaCl = 0.15 mole

Step 4:

Determination of the mass of NaCl. This is illustrated below:

Mole of NaCl = 0.15 mole

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =?

Mass = number of mole x molar Mass

Mass of NaCl = 0.15 x 58.443

Mass of NaCl = 8.77g

Therefore, 8.77g of NaCl is needed to make 1 L of the original solution A.

We need 8.77 grams of NaCl

Explanation:

Step 1: Data given

Volume of solution A = 16 mL = 0.016 L

Volume of solution B = 300 mL = 0.300 L

Concentration of solution B = 0.50 M

Step 2: Calculate molarity of solution A

C1*V1 = C2*V2

⇒with C1 = the concentration of solution A = TO BE DETERMINED

⇒with V1 = the volume of solution A = 0.016 L

⇒with C2 = the concentration of solution B = 0.50 M

⇒with V2 = the volume of solution B = 0.300 L

C1 * 0.016 L = 0.50 M * 0.300 L

C1 = 9.375 M

Step 3: Calculate moles of solution A

Moles = molarity * volume

Moles = 9.375 M * 0.016 L

Moles = 0.15 moles

Step 4: Calculate mass of NaCl needed

Mass NaCl = moles / molar mass

Mass NaCl = 0.15 moles * 58.443 g/mol

Mass NaCl = 8.77 grams

We need 8.77 grams of NaCl

false

because it does not have the potential to be entirely used up

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.