A metal salt with the formula MSO4 crystallizes from water to form a solid with the composition MSO4⋅5H2O. At 298 K, the equilibrium vapor pressure of water above this solid is 15.7 Torr.

MSO4⋅5H2O(s)↽−−⇀MSO4(s)+5H2O(g)
What is the value of ΔG for the reaction when the vapor pressure of water is 15.7 Torr?

Δ= ? J/mol

What is the value of Δ for the reaction when the vapor pressure of water is 571 Torr?

ΔG= ? J/mol

The value of Δ for the reaction when the vapor pressure of water is 571 Torr is as follows

Explanation:

At 298 K, the equilibrium vapor pressure of water above this solid is 28.5 Torr.

MSO4⋅5H2O(s)<> MSO4(s)+5H2O(g)

1 atm = 760 torr

thus, 28.5 torr= 0.0375 atm

Kp = [p(H2O)]5 = ( 0.0375)5 = 7.42 into 10-8

What is the value of Δ for the reaction when the vapor pressure of water is 28.5 Torr?

we have, Δ = - RT ln K

in this case K = Kp

Δ = - (8.314 J by K-mol into 298) ln 7.42 into 10-8 = + 40.673 kJ/mol

What is the value of Δ for the reaction at this temperature if the vapor pressure of water is 533 Torr?

533 torr= 0.701 atm

Kp = [p(H2O)]5    = ( 0.701)5 = 0.1697

Δ = - (8.314 J by K-mol into 298) ln 0.1697 = + 4.395 kJ/mo

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.