How many moles of glucose are in 19.1 g of glucose

There are 0,106 mol of glucose in 19,1g.

Explanation:

First we calculate the weight of 1 mole of Glucose whose molecular formula is C6 H12 0 6, with the atomic weights of each element obtained from the periodic table. Then, by means of a simple rule of three we calculate the moles that are in 19.1 grams:

Weight 1 mol C6H1206 = (Weight C)x 6 + (Weight H)x12 + (Weight 0)x6=

                                       = 12 g x 6 + 1g x12 + 16 g x 6= 180 g/mol

180 g 1 mol glucose

19,1 gx= (19,1 g x 1 mol glucose)/ 180 g= 0,106 mol

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