Find the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium and the remainder oxygen.
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The empirical formula of a compound with 26.56% potassium, 35.41% chromium, and the rest being oxygen would be

The number of mole of each element in the compound can be found by dividing each element's percentage with their respective molar weights:

Potassium K = 26.56%

               = 26.56/39.1

                    = 0.68

Chromium, Cr = 35.41%

                       = 35.41/52

                        = 0.68

Oxygen, O = 100 - 26.56+35.41

                     = 38.03/16

                        = 2.38

Divide each number of moles by the smallest.

K = 0.68/0.68

         = 1

Cr = 0.68/0.68

       = 1

O = 2.38/0.68

      = 3.5

Thus, the empirical formula would be

Multiply all by 2 to remove the fraction:

More on empirical formula can be found here; link

Explanation:

First, calculate how much percent of oxygen there is. We know that the whole compound cannot exceed 100%, so we take that, and substract it from 26.56% and 35.41%.

 100.00

-   26.56

-------------------

   73.44

-   35.41

---------------------

   38.03

That is how much of oxygen we have.

Potassium: 26.56% or 26.56g

Chromium: 35.41% or 35.41g

Oxygen: 38.03% or 38.03g

To find the empirical formula, you simply find the amount of mol that each one has. You can do this by using the atomic mass of each element.

We now determine the lowest number and divide each mol by it. In this case, the lowest number is 0.67

Finally, we take each element add add their respective number.

So, this empirical formula would be:

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