This reaction involves two successive Michael reactions, and has the following steps: 1. Deprotonation forms enolate ion 1; 2. The first Michael reaction forms enolate ion 2; 3. The second Michael reaction forms enolate ion 3; 4. Protonation leads to the final product. Write the mechanism out on a sheet of paper, and then draw the structure of enolate ion 1.

The structure is on the attached file.

Explanation:

The reaction entails 2 sequencial Michael's reaction with the steps below.

1. Deprotonation forms enolate ion1.

2.The first Michael's reaction results in enolate ion 2.

3.The second Michael's reaction gives enolate ion 3.

4. Protonation leads to the formation of the final product.

answer; i believe the correct answer is (solid gold);

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.