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Chemistry, 21.04.2020 17:13, fattypickeltoefungus
The activation energy for this reaction is 75 kJ⋅mol−1. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ⋅mol−1. At what temperature would the non‑catalyzed reaction need to be run to have a rate equal to that of the enzyme‑catalyzed reaction at 25 ∘C?
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Chemistry, 21.06.2019 23:30, 23gordns
Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isí‘ťí‘ť=푛푛푛푛푛푛푉푉mo re accurate estimates can be made with the van der waals equationí‘ťí‘ť=í‘›í‘›í‘›í‘›í‘›í‘›í‘ ‰í‘‰â’푛푛푟푟â’푞푞푛푛2í‘ ‰í‘‰2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?
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Chemistry, 23.06.2019 06:20, Lindsay882
Type the correct answer in each box. balance the chemical equation.__ n203 ➡️ __ n2 +__ o2
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The activation energy for this reaction is 75 kJ⋅mol−1. The enzyme catalase, found in blood, lowers...
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