Określ, ile gramów chlorku amonu NH4Cl należy rozpuścić w 300g wody w temperaturze 70oC, aby otrzymać roztwór nasycony.

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About 186 g of  NH₄Cl

Explanation:

The translation of the question is:

Specify how many grams of NH₄Cl, ammonium chloride, should be dissolved in 300g of water at 70ºC to obtain a saturated solution.

plz give it best

Solution

The file attached shows the graph with the solubility curves for a number of solutes in water.

There, I show you the solubility of a solution of NH₄Cl at 70ºC: it is about 62g of NH₄Cl per 100 grams of water.

Then, the amount of  NH₄Cl in 300g of water at that temperature is calculated using proportions:

300 g of water × 62 g of  NH₄Cl / 100 g  of water = 186 g of  NH₄Cl

Temperature and pressure

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)