Chemistry
Chemistry, 19.04.2020 06:20, natalie2sheffield

These equations represent the results of dissolving different substances in water. For each dissolution,
the results of a conductivity test are given. The conductivity test involves placing wires connected to a
battery and a light bulb into the solution. If the solution is able to conduct electricity, the bulb will light.
Identify each substance as a strong electrolyte, weak electrolyte, or nonelectrolyte.
(NH4)2SO4(s) β†’ 2NH4+ (aq) + S04 (aq)
light bulb glows brightly:
CuSO4(s) β†’ Cu2+(aq) + SO42-(aq)
light bulb glows brightly:
HF(g) + H2O(1) → H30+ (aq) + F→ (aq)
light bulb glows faintly:
C3H6O(1) β†’ C3H60(aq)
light bulb does not glow:

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These equations represent the results of dissolving different substances in water. For each dissolut...

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