A student needs to determine the specific heat of a metal. She sets up a calorimeter with 100.0 mL of deionized water at room temperature, 21.0 Celsius. She heats up 50.0g of the unknown metal to 100.0 Celsius. After adding the hot metal to the water in the calorimeter the temperature equilibrated at 28.7 Celsius. What is the specific heat of the metal in J/gC?

The specific heat of the metal is 0.903 J/g°C

Explanation:

Step 1: Data given

Volume water = 100.0 mL = 0.100 L

Temperature = 21.0 °C

Mass of metal = 50.0 grams

Initial temperature of metal = 100.0 °C

Final temperature = 28.7 °C

The specific heat capacity of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Heat lost = heat gained

Qlost = -Qgained

Qmetal = -Qwater

Q = m*c*ΔT

m(metal) * c(metal)*ΔT(metal) = -m(water) * c(water) * ΔT(water)

⇒with m(metal) = the mass of metal = 50.0 grams

⇒with c(metal) = the specific heat of the metal = TO BE DETERMINED

⇒with ΔT(metal) = The change of temperature of the metal = T2 - T1 = 28.7 °C - 100 °C = -71.3 °C

⇒with m(water) = the mass of water = 100.0 ml * 1g/mL = 100 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the chagnge of temperature of water = 28.7 °C - 21.0 °C = 7.7 °C

50.0 * c(metal) * (-71.3) = -100 * 4.184 * 7.7 °C

-3565 * c(metal) = -3221.7

c(metal) = 0.903 J/g°C

The specific heat of the metal is 0.903 J/g°C

i think slash and

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.