What is the molarity of a stock solution if 60 mL were used to make 150 ml
of a .5M solution?

The molarity of the stock solution is 1.25 M.

Explanation:

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 =

Plugin the values as,

M2 =

       = 1.25 M

So the molarity of the stock solution is 1.25 M.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.