Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperature changes from 32 ºC to 57 ºC.

2076.9 J/kg°C

Explanation:

The equation needed here is:

, where q is the energy in Joules, m is the mass in kg, C is the heat capacity, T_f is the final temperature, and T_i is the initial temperature.

Here, we have q = 6.75* J, m = 1.30kg, T_f = 57, and T_i = 32. So:

Solving for C, we get:

C = 2076.9 J/kg°C

Hope this helps!

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

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