There poisonous gas that needs to be removed from a room. The room is at 1 atm and 270 C. A machine can remove the gas at 32 mL/minute. How long will it take to remove all the gas?

1391 minutes

Explanation:

To solve the problem, we need to find first the volume of gas present in the room.

We can do it by using the equation of state for an ideal gas:

where

p = 1 atm is the pressure

V is the volume

n = 1 mol is the number of moles (not given in the problem, so we assume its value)

is the gas constant

is the temperature

Solving for V,

So, there are 44.5 L of gas in the room.

The gas can be removed at a rate of

Therefore, the time it takes is:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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