Imagine it took 300 mL of 0.1 M LiOH to reach the first equivalence point and an additional 300 mL of 0.1 M LiOH (600 mL total) to reach the second equivalence point. How many moles of H2 were in the original acid solution

0.03 mol H₂

Explanation:

In a diprotic acid titration, the first equivalence point relates to the equilibrium:

And the second equivalence point to:

We can add those two equations and we're left with:

So to calculate the moles of H₂ that were in the original acid solution we use the total volume used (in this case 600 mL).

600 mL ⇒ 600/1000 = 0.6 L

We calculate the moles of LiOH, using its molar concentration:

And now we convert moles of LiOH (or OH⁻) to moles of H₂ using the  stoichiometric ratio:

i think its 100.

hope this !