A student placed 11.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0 mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution

There is 0.92 g of glucose in 100 mL of the final solution.

Explanation:

Initially, 11.5 g of glucose is added to the volumetric flask

Water is then added to 100 mL Mark,

The flask was then shaken until the solution was uniform.

The shaking of the mixture makes the concentration of glucose to become uniform all through the solution.

At this point, the concentration of this solution in g/mL is (11.5/100) = 0.115 g/mL

A 40.0 mL sample of this glucose solution was diluted to 0.500 L.

40.0 mL of the already mixed solution is then diluted to 0.500 L.

The mass of glucose in 40.0 mL of the mixed solution with concentration 0.115 g/mL is then given as

Mass = (conc in g/mL) × (volume) = 0.115 × 40 = 4.6 g

So, this mass is then diluted to 0.500 L mark.

New concentration = (mass)/(conc In mL) = (4.6/500) = 0.0092 g/mL

How many grams of glucose are in 100. mL of the final solution

Mass = (conc in g/mL) × (Volume in mL) = 0.0092 × 100 = 0.92 g

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