Given that 2Al(s) + 3 2 O2(g) → Al2O3(s) ΔH o rxn = −1601 kJ/mol and 2Fe(s) + 3 2 O2(g) → Fe2O3(s) ΔH o rxn = −821 kJ/mol calculate the standard enthalpy change for the following reaction: 2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s) Enter your answer in scientific notation. × 10 kJ

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year