Let P and V represent the pressure and volume of the Xe(g) in the container in diagram 3. If a piston is used to reduce the volume of the gas to V2 at a constant temperature, what is the new pressure in the container in terms of the original pressure, P ?

Xe(g) is in a container at a certain pressure (P) and volume (V), If the volume is halved (V₂ = V/2), the pressure is doubled at a constant temperature. That is, P₂ = 2 P.

Let P and V represent the pressure and volume of the Xe(g) in a container. If a piston is used to reduce the volume of the gas to V/2 (V₂) at a constant temperature, we can calculate the new pressure (P₂) using Boyle's law, which establishes that there is an inverse relationship between the pressure and the volume of a gas.

Xe(g) is in a container at a certain pressure (P) and volume (V), If the volume is halved (V₂ = V/2), the pressure is doubled at a constant temperature. That is, P₂ = 2 P.

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2p

Explanation:

To solve this question, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

where

p is the pressure of the gas

V is its volume

The equation can be rewritten as

where in this problem we have:

is the initial pressure of the Xe(g) gas

is the initial volume of the Xe(g) gas

 is the final volume of the Xe(g) gas

Solving for p2, we find the final pressure of the gas:

So, the final pressure is twice the initial pressure.

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