For the decomposition of nitrous oxide at 565 °C 2 N2O → 2 N2 + O2 the following data have been obtained: [N2O], M 2.36 1.20 0.808 0.607 Time, s 0 6.17 12.30 18.50 What is the average rate of disappearance of N2O over the time period from t = 6.17 s to t = 12.30 s (For the answer, just enter the numerical value, 3 sig digs)

The closer the atoms are to becoming ionic the more highly dense the negatively charged side gets.

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -

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50? i have no !