You prepare a buffer solution from 10.0 mL of 0.100 M MOPS (3‑morpholinopropane‑1‑sulfonic acid) and 10.0 mL of 0.074 M NaOH . 0.074 M NaOH. Next, you add 1.00 mL of 3.51 × 10 − 5 M 3.51×10−5 M lidocaine to this mixture. Denoting lidocaine as L, calculate the fraction of lidocaine present in the form LH +

The fraction of lidocaine is 0.999

Explanation:

The number of moles of MOPS:

The number of moles of NaOH:

In 20 mL of solution, the molarity is:

The acid form is:

1x10⁻³ - 7.4x10⁻⁴ = 2.6x10⁻⁴moles

About lidocaine, the pKa is:

Ka = 1x10⁻¹⁴/8.7x10⁻⁷=1.15x10⁻⁸

The fraction of lidocaine is:

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

explanation:

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