3) The value of Keq for the equilibrium H2 (g) + I2 (g) 2 HI (g) is 54.0 at 427 °C. What is the value of Keq for the equilibrium below? HI (g) 1/2 H2 (g) + 1/2 I2 (g)

The equilibrium constant for this reaction is 0.136

Explanation:

Step 1: Data given

H2 (g) + I2 (g) ⇆ 2 HI (g)  Kc = 54.0

Temperature = 427 °C

Step 2: The balanced equation

HI (g) ⇆ 1/2 H2 (g) + 1/2 I2 (g)

Step 3: Calculate Kc for 1/2H2 (g) + 1/2I2 (g) ⇆  HI

Kc' = √(Kc)

Kc' = √(54.0)

Kc' = 7.35

Step 4: Calculate Kc for HI (g) ⇆ 1/2 H2 (g) + 1/2 I2 (g)

Kc" = 1/Kc'

Kc" = 1/ 7.35

Kc" = 0.136

The equilibrium constant for this reaction is 0.136

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the population of unionid mussels in the hudson river decreased after zebra mussels were introduced. zebra mussels, a nonnative species, competed with the unionid mussels for food. the zebra mussels were able to outcompete the unionid mussels, allowing the zebra mussel population to increase dramatically over six years. the unionid mussel population decreased due to a lack of food.

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