A 22.4 liter sample of gas at STP weighs 12.0 grams. What is the molecular weight of the gas?

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32.0 g/mol

16.0 g/mol

12.0 g/mol

29.4 g/mol

d

12.0g/mole

Explanation:

Since the gas is at STP, it'll have standard values of temperature and pressure at STP

V = 22.4L

m = 12.0g

T = 273.15

P = 1.0 atm

R = 0.082 L.atm / K.mol

Using ideal gas equation,

PV = nRT

n = no. Of moles

n = PV / RT

n = (1.0 * 22.4) / (0.082 * 273.15)

n = 22.4 / 22.3983

n = 1.00

But number of moles (n) = mass (m) / molar mass (M)

n = m / M

M = m / n

M = 12.0 / 1.0

M = 12g/mol

The molar mass of the gas is 12.0g/mole

3 1/4 %

explanation:

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.