The standard enthalpy change for the combustion of 1 mole of propane is –2043.0 kJ. C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) Calculate ΔfH° for propane based on the following standard molar enthalpies of formation. molecule ΔfH° (kJ/mol-rxn) CO2(g) –393.5 H2O(g) –241.8'
Answers: 3
![\Delta H^o_{rxn}=[(3\times \Delta H^o_f_{(CO_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(1\times \Delta H^o_f_{(C_3H_8(g))})+(5\times \Delta H^o_f_{(O_2(g))})]](/tpl/images/0604/1723/6eb42.png)
![-2043.0=[(3\times (-393.5))+(4\times (-241.8))]-[(1\times \Delta H^o_f_{(C_3H_8(g))})+(5\times (0))]\\\\\Delta H^o_f_{(C_3H_8(g))}=-104.7kJ/mol](/tpl/images/0604/1723/1b82f.png)
is -104.7 kJ/mol
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The standard enthalpy change for the combustion of 1 mole of propane is –2043.0 kJ. C3H8(g) + 5 O2(g...
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