The surface area of an object to be gold plated is 49.8 cm2 and the density of gold is 19.3 g/cm-3. A current of 3.15. A is applied to a solution that contains gold in the +3 oxidation state. Calculate the time required to deposit an even layer of gold 1.2 x 10 -3cm thick on the object.

Time required to deposit an even layer of gold with given thickness is sec.

Explanation:

The given data is as follows.

     Surface area = 49.8 ,

     Density of gold = 19.3 ,

     Current = 3.15 A,       thickness of gold layer =

It is known that relation between volume, area and thickness is as follows.

           V = Surface area × Thickness

               =

               = 0.05988

Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

        = sec

Thus, we can conclude that time required to deposit an even layer of gold with given thickness is sec.

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