What is the volume of 3.66 x 1032 molecules of fluorine gas at STP?

1.36x10^10L

Explanation:

Step 1:

Determination of the mole of fluorine that contains 3.66x10^32 molecules. This is shown below:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of fluorine also contains 6.02x10^23 molecules.

Now if 1 mole of fluorine contains 6.02x10^23 molecules,

Therefore, Xmol of fluorine will contain 3.66x10^32 molecules i.e

Xmol of fluorine = 3.66x10^32/6.02x10^23

Xmol of fluorine = 6.08x10^8 moles

Step 2:

Determination of the volume occupied by 6.08x10^8 moles of fluorine.

1 mole of any gas occupy 22.4L at stp. This means that 1 mole of fluorine also occupy 22.4L at stp.

Now if 1 mole of fluorine occupies 22.4L at stp,

Then 6.08x10^8 moles of fluorine will occupy = 6.08x10^8 x 22.4 = 1.36x10^10L

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.