A student prepares a aqueous solution of 4chlorobutanoic acid . Calculate the fraction of -chlorobutanoic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to significant digits.

Incomplete question: The concentration of the aqueous solution is 0.65 mM

The percentage of dissociation is 19.23%

Explanation:

The pKa of the 4-chlorobutanoic acid is 4.53, thus:

The initial concentration is 0.65 mM = 6.5x10⁻⁴M

The reaction is:

                   HA        +         H₂O        =         H₃O⁺        +         A⁻

I                6.5x10⁻⁴                                          0                       0

C               -x                                                   +x                      +x

E              6.5x10⁻⁴ -x                                      x                        x

The Ka is:

The percentage of dissociated is:

%

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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