What is the molarity of the solution produced when 145 g NaCl is dissolved in sufficient water to prepare 2.75 L of solution? *

a. 0.0190
b. 52.7
c. 399
d. 0.902

Given:

We know the molar mass,

Now,

The molar mass of NaCl will be:

=

=

The amount of moles will be:

=

=

=

hence,

The molarity will be:

→

By substituting the values,

Thus the above approach i.e., "option d" is correct.

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Option D) 0.902M

Explanation:

Sodium chloride has a chemical formula of NaCl

Given that,

Amount of moles of NaCl (n) = ?

Mass of NaCl in grams = 145g

For molar mass of NaCl, use the molar masses:

Sodium, Na = 23g;

Chlorine,Cl = 35.5g

NaOH = (23g + 35.5g)

= 58.5g/mol

Since, amount of moles = mass in grams / molar mass

n = 145g / 58.5g/mol

n = 2.48 mole

Amount of moles of NaCl (n) = 2.48 mole

Volume of NaCl solution (v) = 2.75L

Concentration of NaCl solution (c) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 2.48 mole / 2.75L

c = 0.9018M

Approximately, c = 0.902M

[c is the concentration in moles per litres which is also known as molarity]

Thus, the molarity of the solution is 0.902M

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.

2b2t

explanation:

2b2t