Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li(s) + N2(g) → 2Li3N(s) How many moles of lithium are needed to produce 0.45 mol of Li3N when the reaction is carried out in the presence of excess nitrogen?

 1.35 moles of are needed to produce 0.45 mol of

Explanation:

The balanced chemical reaction is ;

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

2 moles of require = 6 moles of

Thus 0.45 moles of will require= of

Thus 1.35 moles of are needed to produce 0.45 mol of

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.