What mass of water will change its temperature by 3.00 °C when 595 J of heat is added to it? The specific heat of water is 4.2 J/g °C

M = 36.5g

^ degrees sign

Q energy heat in JOULES J

m mass of the sample in GRAMS g

C specific heat in J/g^C

ΔT change in temperature ^C
or final temp- initial temp

Based on the information you've provided, we know the following variables:

ΔT= 3^C

Q = 525 J

C= 4.8 J
g×^C

All we have to do is rearrange the equation to solve for m. This can be accomplished by dividing both sides by C and ΔT to get m by itself like this:

m= Q
ΔT×C

Now, we just plug in the known values:

m= 525 J
3^C×4.8 J
g×^C

m=36.5g

That result from subduction of oceanic plates beneath lighter continental plates. most of the earth's volcanoes are located around the pacific ring of fire because that the location of most of the earth's subduction zones.