Chemistry, 14.04.2020 21:20, Richelleypinelley

For the concentration cell, Pb(s) | PbSO4(s), NH4+ (3.0M), SO42-(1.50M), NO3- (0.10M), Pb2+(? M) || Pb(NO3)2(0.05 M) | Pb(s), Ecell = -(0.0257/2)ln(x/0.05), what is the expression for x in terms of Ecell ? {The notation used here is exp[x] = ex where "e" is the base of natural logarithm.}

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For the concentration cell, Pb(s) | PbSO4(s), NH4+ (3.0M), SO42-(1.50M), NO3- (0.10M), Pb2+(? M) ||...