A sample of argon gas at a standard pressure occupies 900 mL at constand temp what volume does the gas occupy if the presure increases to 850mmHg
options:
A 760mL
B 805mL
C 950mL
D 1053mL

B .805 mL

Explanation:

Here, temperature is constant!

so we can use P1V1=P2V2

P1,V1 is pressure and volume in original condition

and P2V2, pressure and volume in new condition!

now, volume is given 900mL(=V1)

standard pressure is 1 atm i.e, 760mmHg(=P1)

pressure increases to 850mmHg(=P2)

now we have,

P1V1=P2V2

i.e, 760mmHg×900mL=850mmHg×V2

i.e, V2={(900×760)/850 } mL

=804.75 mL

≈805mL

✌️:)

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.