The free energy change for the following reaction at 25 °C, when [Cd2+] = 1.20 M and [Fe2+] = 1.40×10-3 M, is -23.9 kJ: Cd2+(1.20 M) + Fe(s) Cd(s) + Fe2+(1.40×10-3 M) ΔG = -23.9 kJ What is the cell potential for the reaction as written under these conditions? -24.07 V Would this reaction be spontaneous in the forward or the reverse direction?

It's spontaneous in the reverse direction

Explanation:

A negative voltage indicate s that the reverse reaction is spontaneous (i.e. oxidation at the cathode, and reduction at the anode; by convention you would need to swap the labels on the electrodes)

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: