A man heats a balloon in the oven. If the balloon initially has a volume of 0.3 liters and a temperature of 25 0C, what will the volume of the balloon be after he heats it to a temperature of 275 0C?

0.55L

Explanation:

Given that,

Original volume of balloon (V1) = 0.3L

Original temperature of balloon (T1) = 25.0°C

[Convert 25.0°C to Kelvin by adding 273

25.0°C + 273 = 298K]

New volume of balloon (V2) = ?

New temperature of balloon (T2# = 275.0°C

[Convert 25.0°C to Kelvin by adding 273

275.0°C + 273 = 548K]

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

0.3L/298K = V2/548K

To get the value of V2, cross multiply

0.3L x 548K = 298K x V2

164.4L•K = 298K•V2

Divide both sides by 298K

164.4L•K /298K = 298K•V2/298K

0.55L = V2

Thus, the new volume of the balloon would be 0.55 litres

i would say b

explanation:

but i think i would need more information than that

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.