When 435 J of heat is added to 3.4 g of olive oil at 21°C, the temperature increases to 98°C. What is the specific heat of olive oil?

The answer to your question is Cp = 1.66 J/g°C

Explanation:

Data

Heat = Q = 435 J

Mass = m = 3.4 g

Temperature 1 = T1 = 21°C

Temperature 2 = T2 = 98°C

Specific heat = Cp = ?

Process

1.- Write the formula of heat

    Q = mCp(T2 - T1)

-Solve for Cp

     Cp = Q / m(T2 - T1)

2.- Substitution

     Cp = 435 / 3.4(98 - 21)

3.- Simplification

      Cp = 435 / 3.4(77)

      Cp = 435 / 261.8

4.- Result

      Cp = 1.66 J/g°C

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.