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A 0.3205 g sample of CaCO3 was dissolved in HCl and the resulting solution was diluted to 250.00 mL in a volumetric flask.
From this volumetric flask, 25.0 mL solution was obtained and titrated against EDTA. A 18.75 ml of EDTA was utilized to reach the end point (Eriochrome Black T used as
the indicator)
Calculate the moles of CaCO3 used:
Hint: Moles = g/MW Use 20ca40 6C12 and 8016
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Answers: 1
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A 0.3205 g sample of CaCO3 was dissolved in HCl and the resulting solution was diluted to 250.00 mL...
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