If 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate,
what mass of Calcium Phosphate will be formed according to the reaction:

55.83 grams is the mass of Calcium Phosphate will be formed according to the reaction when 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate.

Explanation:

Data given:

mass of calcium sulphate reacted= 75.2 grams

atomic mass of calcium sulphate = 136.14 grams/mole

balanced chemical reaction equation:

3CaS +2 (P)   ⇒   (P) + 3S

number of moles of calcium phosphate given will be calculated as:

number of moles =

        putting the values in the above formula, we get

number of moles =

                             = 0.55 moles of CaS is given

From the balanced equation:

3 moles of CaS reacts to give 1 mole of calcium phosphate

so, 0.55 moles of CaS will react to form x moles of calcium phosphate

=

3x = 0.55

x = 0.18 moles of calcium phosphate is formed

mass = number of moles x atomic mass of calcium phosphate

(atomic mass of (P) =310.18 grams/mole)

putting the values in the formula:

mass = 0.18 x 310.18

          = 55.83 grams of calcium phosphate is formed.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2