Which has the larger percent composition of sulfur, H2SO3 or H2S2O8?

H₂SO₃ has the larger percent composition of sulfur when compared to H₂S₂O₈.

Explanation:

To find the largest percent of composition of sulfur, we have to divide the mass of sulfur divided by the total mass of the molecule multiplied by 100.

H₂SO₃

Mass of H = 1 × 2 = 2

Mass of S = 32×1 = 32

Mass of O = 16 × 3 = 48

Total mass of H₂SO₃ = 82 g

Total mass of H₂S₂O₈ = 2+ (2×32) + (8×16) = 194

Percent composition of S in H₂SO₃ =

                                                         = 39%

Percent composition of S in H₂S₂O₈ =

                                                           = 32.9 ≈ 33 %

sry but any answer choices