At what temperature (inc) would the volume a gas be equal to 45.7L if the volume of gas was 33.9L at 12.4c

The answer to your question is  T1 = 384.7 °K

Explanation:

Data

Volume 1 = V1 = 45.7 l

Temperature 1 = T1 = ?

Volume 2 = V2 = 33.9 l

Temperature 2 = T2 = 12.4°C

To solve this problem use Charles' law

              V1/T1 = V2/T2

                    T1 = V1T2/V2

-Convert temperature to °K

T2 = 12.4 + 273 = 285.4°K

-Substitution

                    T1 = (45.7 x 285.4) / 33.9

-Simplification

                    T1 = 13042.8 / 33.9

-Result

                    T1 = 384.7 °K

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o