What happens to a reaction at equilibrium when the concentration of the PRODUCTS is increased ?

Equilibrium shift to left, favoring the formation of reactants.

Explanation:

Take the equation below as an instance

CaCO3(s) ⇌CaO(s) + CO2(g)

Once, concentration of the PRODUCTS,

CaO(s) and CO2(g) are increased, the equilibrium constant, K remains the same while the equilibrium position shift to the left, favoring the formation of reactant, CaCO3(s)

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.