29) Which statement explains why 10.0 mL of a 0.50 M H2504(aq) solution exactly neutralizes 5.0
mL of a 2.0 M NaOH(aq) solution?
A)
The moles of H(aq) equal the moles of OH(aq).
B)
The moles of H2502(aq) equal the moles of NaOH(aq).
C)
The moles of H2SO4(aq) are greater than the moles of NaOH(aq).
D)
The moles of H(aq) are greater than the moles of OH(aq).

Rethink and reinvent

The answer is conduction

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.