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How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

The answer to your question is 37.5 l of water vapor

Explanation:

Data

volume of ethane = 12.5 l

volume of water vapor = ?

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒   4CO₂  +  6H₂O

-Convert the volume of C₂H₂ to moles

                    1 mol of C₂H₂ 22.4 l

                    x                     12.5 l

                             x = (12.5 x 1) / 22.4

                             x = 0.56 moles

-Calculate the moles of water vapor

                 2 moles of C₂H₂ 6 moles of H₂O

                 0.56 moles of C₂H₂  x

                          x = (0.56 x 6) / 2

                          x = 1.67 moles of H₂O

-Calculate the volume of water vapor

                          22.4 l of H₂O 1 mol

                             x                   1.67 moles

                             x = (1.67 x 22.4) / 1

                             x = 37.5 l

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.