A gas has a temperature of 12 C and a volume of 3.5 liters. If the temperature is raised to 29 C and the pressure is not altered, what is the volume of the new gas?

The answer to your question is  V2 = 3.7 l

Explanation:

Data

Temperature 1 = T1 = 12 °C

Volume 1 = V1 = 3.5 l

Temperature 2 = T2 = 29 °C

Volume 2 = V2 = ?

To solve this problem use Charles' law

            V1/T1 = V2/T2

-Solve for V2

            V2 = V1T2 / T1

Process

1.- Convert temperature to °K

Temperature 1 = 12 + 273 = 285°K

Temperature 2 = 29 + 273 = 302 °K

2.- Substitution

             V2 = (3.5 x 302) / 285

3.- Simplification

              V2 = 1057 / 285

4.- Result

              V2 = 3.7 l

answer; i believe that the correct answer is (a) potassium(k)