The ionization energy for potassium 419 kj/mol. the wavelength of light emitted when an excited k atom undergoes the 4s< 4p transition is approximately 769 nm. using this info, calculate the energies of the 4s and 4p orbitals in potassium.

Answer : The energies of the 4s and 4p orbitals in potassium is,

Solution :

First we have to calculate the change in energy.

Formula used :

where,

= change in energy

h = Planck's constant =

c = speed of light =

=

Now put all the given values in this formula, we get

The difference in energy levels is defined as,

Now we have to calculate the first ionization energy for one atom of potassium.

Now this ionization energy will be equal to the negative of the orbital energy of the electron located in the 4s-orbital.

Now we have to calculate the energy of the 4p orbital in potassium.

Therefore, the energies of the 4s and 4p orbitals in potassium is,

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

1.solid

2.carbon dioxide

3.helium