Please help I am so bad at chemistry!!

The answer to your question is below

Explanation:

Data

3.- grams of reactant

volume = 1l

a) 0.5 M NaCl

-Calculate the number of moles

moles = Molarity x volume

moles = 0.5 x 1

moles = 0.5

-Calculate the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

               58.5g 1 mol

                  x      0.5 mol

                   x = (0.5 x 58.5) / 1

                   x = 29.25 grams of NaCl

b)

-Calculate the moles

moles = 2 x 1

moles = 2

-Calculate the molar mass of CaCl₂

CaCl₂ = 40 + 71 = 142 g

-Calculate the grams

          142 g 1 mol

             x       2 moles

             x = (2 x 142) / 1

             x = 284 grams of CaCl₂

c) 1.5 M NaOH

-Calculate the moles of NaOH

moles = 1.5 x 1

moles = 1.5

-Calculate the molar mass of NaOH

NaOH = 23 + 16 + 1 = 40 g

-Calculate the grams

          40 g 1 mol

             x   1.5 moles

             x = (1.5 x 40)

             x = 60 grams of NaoH

4.- mass of fructose = ?

Volume = 1l

Molarity = 0.75

-Calculate the moles of fructose

moles = 0.75 x 1

moles = 0.75

-Calculate the molar mass of fructose

C₆H₁₂O₆ = (12 x 6) + (12 x 1) + (16 x 6) = 72 + 12 + 96

                                                            = 180 g

-Calculate the grams of fructose

                 180 g 1 mol

                   x      0.75 moles

                   x = (0.75 x 180) / 1

                   x = 135 g of fructose

5.- Balanced chemical reaction

           3Ba(NO₃)₂  +  Al₂(SO₄)₃   ⇒   3BaSO₄  +  2Al(NO₃)₃

-Calculate the moles of Al₂(SO₄)₃

moles = molarity x volume

moles = 0.35 x 0.025

          = 0.00875

-Use proportions to calculate the moles of Ba(NO₃)₂

                3 moles of Ba(NO₃)₂ 1 mol of Al(SO₄)₃

                 x                                0.00875 moles of Al(SO₄)₃

                                     x = (0.00875 x 3) / 1

                                     x = 0.02625

-Calculate the volume of 0.280 M solution of Ba(NO₃)₂

volume = moles / molarity

volume = 0.02625 / 0.280

volume = 0.0938 l or 93.8 ml

5.- Balanced chemical reaction

           2AgNO₃  +  CaBr₂   ⇒   2AgBr  + Ca(NO₃)₂

- Calculate the moles of CaBr₂

moles = 0.128 x 0.035 = 0.0045

- Calculate the moles of AgNO₃

         2 moles of AgNO₃ 1 mol of CaBr₂

          x                             0.0045 moles

                     x = (0.0045 x 2) /1

                     x = 0.009 moles

- Calculate the volume of AgNO₃

Volume = moles / Molarity

             = 0.009 / 0.415

             = 0.0215 l  or 21.6 ml

the answer is barium and copper bromide