What is the pressure of 0.500mol of gas at 12.2 L and 273K

P = 0.92 atm

Explanation:

Given data:

Pressure of gas = ?

Number of moles = 0.500 mol

Volume of gas = 12.2 L

Temperature of gas = 273 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

P = nRT/v

P = 0.500 mol × 0.0821 atm.L/ mol.K   ×273 K/ 12.2 L

P = 11.2 /12.2 L

P = 0.92 atm

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.