answer : (a) volume of the gas = 8.67 Γ l
(b) second virial coefficient b = -1.21226 l/mole
solution : given, t = 300k
p = 20atm
z = 0.86
n = 8.2 mmoles = 8.2 Γ moles
r = 0.082 l atm/k/mol
find, (a) volume of gas and (b) second virial coefficient b at 300k.
formula used :
and
(a)
= \times 0.082\times 300}{20}[/tex]
= 8.67 Γ l
(b)
= (0.00867-1) Γ 8.659
= - 8.5839 l/mole