PLEASE HELP 9.26 g of an unknown solid is dissolved in a coffee cup calorimeter that contains 62.0 mL of water.
The measured temperature increased from 23.4 °C to 24.7 °C. The specific heat of water is 4.184Jg
10c-1 and assume the density of the solution is 1.00 g mlº? Calculate the molecular weight of the
unknown solid if the AH was determined to be -2.51 k) moll via another experiment.

Then you use the specific heat of the solution and the number of moles of the solute ... What is the molar heat of ammonium nitrate if 8.00 g of NH₄NO₃ dissolved in 50.0 g of water in a coffee cup calorimeter causes the temperature to drop by 10.1 °C? Assume that the specific heat capacity of the solution is 4.18 J·°C⁻¹g⁻¹.

Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied