Consider the three equations below. Superscript 14 subscript 7 upper N plus superscript 1 subscript 1 upper H right arrow superscript 15 subscript 8 upper O. Superscript 4 subscript 2 upper H e plus superscript 4 subscript 2 upper H e right arrow superscript 8 subscript 4 upper B e. Superscript 28 subscript 14 upper S i plus 7 superscript 4 subscript 2 upper H e right arrow superscript 56 subscript 28 upper N i. Which statement do these reactions best support?

the millers tale is the answer.

i think it's letter a.

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.