Write 2ki(aq)+pb(no3)2(aq)→pbi2(s)+2kno3( aq) as a sentence

ha- i know this is not a sentence.. but here-

chop up up all (aq) molecules into their ions.you may perceive them from the equation, because of the fact in a double alternative, the ions exchange places. The separated equation is the completed ionic equation. Pb^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + 2I^-(aq) ? PbI2(s) + 2K^+(aq) + 2NO3^-(aq) Now do away with all entities which take place on the two aspects of the arrow interior a similar state. for this reason, it is going to likely be the ok^+ and NO3^- ions, that are all in (aq) state on the two aspects and are the spectator ions. This leaves you with Pb^2+(aq) + 2I^-(aq) ? PbI2(s) it somewhat is the internet ionic equation. a speedy thank you to work out what ions are spectators is checking what ions do no longer exchange state. The entities that vary in state are the reacting ions and could seem interior the internet equation.

h