\ce{2H2O2 -> 2H2O + O2}2HX

2



OX

2





2HX

2



O+OX

2



How many moles of \ce{H2O}HX

2



O will be produced from 26.0 \text{ g}26.0 g26, point, 0, start text, space, g, end text of \ce{H2O2}HX

2



OX

2



?

0.765 moles H₂O

Explanation:

Based on the reaction:

2 H₂O₂ → 2 H₂O + O₂

2 moles of H₂O₂ produce 2 moles of H₂O

26g of H₂O₂ are:

26.0g H₂O₂ × (1mol / 34g) = 0.765 moles of H₂O₂.

Moles of H₂O are:

0.765 mol H₂O₂ × (2 mol H₂O / 2 mol H₂O₂) = 0.765 moles H₂O.

That means, 0.765 moles of H₂O are produced from 26.0g of H₂O₂

i think that the answer is c